Question

I will give you brainliest if you answer this question truthfully please i need it urgently...​

Answer 1

In Triangle ADB and Triangle ADC

Angle BAD = Angle CAD (given)

AB = AC (given)

AD = AD (Common)

Hence triangle ADB ≅ ADC (SAS)

Angle B = Ancle C (C.P.C.T)

BD = DC (C.P.C.T)

Angle BDA = Angle CDA

Angle bda + angle cda = 180

2 Angle Bda = 180

Angle BDA = 90

Both angles will be 90, hence it is perpendicular.

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Answer 2

In ABD and ACD

AD=AD common

AB=AC given

BAD=CAD given

therefore ABD=~ACD

hence B= C cpct

and ADB=ADC cpct

but BC is a straight line

so ADB+ADC=180°

2 ADC =180°

ADC =90° =ADB

hence AD is perpendicular to BC

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