Question

I will mark as brainiest​

Answer 1

Answer:

base area (a) is 0.15m

thickness 1.0cm =0.01m

boiling rate is 6kg

mass is 6kg

time 1min =60sec

thermal conductivity of brass k=109jsmk

heat of vapourisation l =2256×1000

the amount of heat flowing into water through the brass base of the boiler is given by

£ Ka(t1-t2)t/l (I)

T1 water flame

T2 bowling water at 100•c

heat required for boiling the water

£ ml ii

equating equation 1 and 2we get

: ml =Ka (t1-t2)t/l

t1-t2=mli /kat

=6×2256×1000× 0.01

=137.98°c

therefore the temp. is137.98°c