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Q. the capacity of an open cylindrical tank is 2079 m^3 and the diameter of its base is 21 m find the cost of plastering its inner surface at ₹ 40 per square metre
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volume = pi× r^2 × h
2079 = 22/7 × (21/2)^2 ×h
2079 * 7 *4/22 * 441 = h
6m = h
Area for plastering = pi ×r (2h + r)
= putting values
(33×45)/2
= 742.5sq.m
Cost = 40 × 742.5
29,700 Rs
PLZ mark it brainliest
2079 = 22/7 × (21/2)^2 ×h
2079 * 7 *4/22 * 441 = h
6m = h
Area for plastering = pi ×r (2h + r)
= putting values
(33×45)/2
= 742.5sq.m
Cost = 40 × 742.5
29,700 Rs
PLZ mark it brainliest
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