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Subtract 3a +5b – 2c from the sum of 4a – b and 2c – 3b.
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Answer:
3b−c
Step-by-step explanation:
Solution
5b−4c+a+2c−3b−4a=−2c+2b−3a
a+2b−3c+2c−3b−4a=−3s−b−c
(−2c+2b−3s)−(−3a−b−c)
−2c+2b−3a+3a+b+c
=3b−c
I have given the explanation
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