Question

I will mark as brainliest
this is a very tricky question
all the rubbish will be temporarily suspended from brainly for 7 days
see the figure
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Answer 1

Answer:

∠PCA = 30°

Step-by-step explanation:

Given : PQ is a tangent, AB is diameter, ∠CAB = 30°

To Find : ∠PCA = ?

In △AOC,

∠CAB = ∠OCA  { angles opposite to equal sides are equal }

So, ∠CAB = ∠OCA = 30°

Since, OC ⊥ PQ  { tangent is perpendicular to the radius at point of contact }

∠PCO = 90°

∠OCA + ∠PCA = 90°

30° + ∠PCA = 90°

∠PCA = 90° - 30°

∠PCA = 60°