Question

I will mark as brainliest who has the clearest explanation and the correct answer.

Answer 1

Solutions :

Question a)

a) How many minutes did Machine B take to pack 2120 more packets of biscuits than Machine A?

Answer a)

We will make equations and solve according to it .

= 92 x 10 = 920

= 920 + 2120 = 3040

= 130 - 92 = 38

$\implies\sf{ \frac{3040}{8} } = 80$

Hence, 80 minutes did Machine B take to pack 2120 more packets of biscuits than Machine A.

Question b)

How many packets of biscuits did both machine pack altogether for that duration?

Answer b)

=80 x (92 + 130)

= 17760 packets.

Hence, 17760 packets of biscuits did both machine pack altogether for that duration.

Question c)

Given that both machines stopped packing at 15 : 45 , at what time did machine a start to pack the biscuits ?

Answer c)

1415 ------- 10 minutes ------ 1

425 ------ 80 min ------- 1545......

Hence, 1415 h ...

Hence ,

a) 80 minutes .

b) 17760 packets.

c) 1415 h

Answer 2

Answer:

Answer a)

We will make equations and solve according to it .

= 92 x 10 = 920

= 920 + 2120 = 3040

= 130 - 92 = 38

\implies\sf{ \frac{3040}{8} } = 80⟹

8

3040

=80

Hence, 80 minutes did Machine B take to pack 2120 more packets of biscuits than Machine A

.Answer b)

=80 x (92 + 130)

= 17760 packets.

Hence, 17760 packets of biscuits did both machine pack altogether for that duration

Answer c) 1415 ------- 10 minutes ------ 1

425 ------ 80 min ------- 1545......

Hence, 1415 h ...

Hence ,

a) 80 minutes .

b) 17760 packets.

c) 1415 h