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class 9 maths ch1
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Step-by-step explanation:
Given:-
5^(x-3) . 3^(2x-8) = 225
To find :-
Find the value of x ?
Solution :-
Given that :
5^(x-3) . 3^(2x-8) = 225
225 can be written as
225=15×15 = (3×5)×(3×5) = 3^2 × 5^2
5^(x-3) . 3^(2x-8) = 5^2 × 3^2
On comparing both sides then
=> x-3 = 2 and 2x-8 = 2
Since x^m = x^n => m = n
=> x = 2+3 and 2x = 2+8
=> x = 5 and 2x = 10
=> x = 5 and x = 10/2
=> x = 5 and x = 5
Therefore, x = 5
Answer:-
The value of x for the given problem is 5
Check:-
If x = 5 then LHS of the given equation
=> 5^(x-3) . 3^(2x-8)
=> 5^(5-3) × 3^(2×5-8)
=> 5^2 × 3^(10-8)
=> 5^2 × 3^2
=> 5×5×3×3
=> 225
=> RHS
LHS = RHS is true for x = 5
Verified the given relations in the given problem.
Used formulae:-
- If x^m = x^n then m = n
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