Question

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A bus covers a distance of ao km at a uniform speed.
the speed had been 15 km/hr more, it would have
take
30 minuites less for the
journey.
find the original
speed of the bus.​

Answer 1

Step-by-step explanation:

total distance = 90

Increased speed = x+15

90/x - 90/x+15=1/2

90(1/x - 1/x+15)=1/2

90(x+15-x/x^2+15x)=1/2

equation is:

x^2+15x-2700=0

x^2+60x-45x-2700=0

x(x+60)-45(x+60)=0

(x+60)(x-45)=0

x= -60, x=45

reject the negative value = -60

usual speed=45 km/ hr

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