Question

I Will Mark As The Brainliest......

The volume of a sphere is given by V = 4/3(pi)R^3
R is the radius of the sphere
The rate of change of volume with respect to R and the change in volume of the sphere as the radius is increased from 20.0 cm to 20.1 cm respectively are

(Assume that the rate does not appreciably change between 20.0 cm to 20.1 cm)

1) 4(pi)R^2 , 160(pi) cm^3
2) 4(pi)R^2 , 1600(pi) cm^3
3) 4(pi)R^2 , 16(pi) cm^3

HINT : Use differentiation

Answer 1

Answer:

2 is the answer but it can be incorrect also but as I solved the answer was 2

but my physics is not good