Question

I WILL MARK BRAINLEST study the following circuit and find out​

Answer 1

First let us make the connections into series one

So 1/R=r1+r2/r1×r2

= 2/24

=1/12

=>R = 12ohm

We know that current in a series connection is always constant

so

I =v/r
r=12×2
=24ohm

I=6/24

=0.25 A

No there wont be any change in the reading

Answer 2

1/24+1/24=R1

R1=24/2

R1=12 ohm

R=R1+R2

= 12+12ohm

=24 equivalent

V=IR

I= V/R

=6/24

=1/4

=0.25A

Therefore,

the reading of the A1, A2

is 0.25A