Math, asked by TahaZubairi, 1 month ago

I will mark brainliest​

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Answered by Unknown867
3

\begin{tabular}{|c|c|c|c|}</p><p></p><p>\cline{1-4}</p><p></p><p>\multicolumn{4}{|c|}{Elementary Particles} \\</p><p></p><p>\cline{1-4}</p><p></p><p>\multicolumn{2}{|c|}{Fermions} &amp;</p><p></p><p>\multicolumn{2}{c|}{Bosons} \\</p><p></p><p>\cline{1-4} Quarks &amp; Leptons &amp; Gauge Bosons &amp; Scalar Bosons \\</p><p></p><p>\cline{1-4} Up &amp; Electron &amp; Photon &amp; Higgs Boson \\</p><p></p><p>Down &amp; Electron Neutrino &amp; W and Z Bosons &amp; \\</p><p></p><p>Charm &amp; Muon &amp; Gluons &amp; \\</p><p></p><p>Strange &amp; Muon Neutrino &amp; &amp; \\</p><p></p><p>Top &amp; Tau &amp; &amp; \\</p><p></p><p>Bottom &amp; Tau Neutrino &amp; &amp; \\</p><p></p><p>\cline{1-4}</p><p></p><p>\end{tabular}

Answered by Anonymous
15

If the probability of atleast one failure is greater than or equal to 31/32, the p lies in the interval. Hence, for 5 events, the probability of no failure is p5. \displaystyle \sf \red{\int \limits^{ \frac{ \pi}{2} }_{0} \frac{3 \sqrt{ \cos \theta} }{( \sqrt{cos \theta} + \sqrt{sin \: \theta}) {}^{5} } \: d \theta}

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