Question

i will mark brainliest For the reaction 2 N2 H4 (l) + N2 O4 (l) -------> 3 N2 (g) + 4H2 O(l) , if 160 g of N2 H4 is mixed with 160 g N2O4, the yield of H2O is

Answer 1

Answer:

125.28 g

Explanation:

N2O4 is a limiting reactant in this case. 160g of N2O4 contains 1.74 moles. Now 1 mole of N2O4 produces 4 moles of H2O. So accordingly 1.74 moles of N2O4 will produce 4×1.74=6.96 moles of H2O. The mass of H20 produced will be

mass= no. of moles × molar mass

= 6.96 × 18

= 125.28 g

so,

mass of H2O produced in this reaction is approximately 125g