I will mark brainliest on solving this.
x+y=4 and 1/x+1/y=4 then the value of x³+y³=??
Pls solve step-by-step
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Answered by
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x+y=4
1/x+1/y=4
x+y/xy=4
4/xy=4
xy=1
x^3+y^3=(x+y)^3 - 3xy(x+y)
=4^3 - 3(1)(4)
=12-12
=0
1/x+1/y=4
x+y/xy=4
4/xy=4
xy=1
x^3+y^3=(x+y)^3 - 3xy(x+y)
=4^3 - 3(1)(4)
=12-12
=0
Answered by
0
Answer:
Step-by-step explanation:
Plz i have don hard work plz mark me brainliest it would be mine 1 st brainliest answer
x+y=4
1/x+1/y=4
x+y/xy=4
4/xy=4
xy=1
x^3+y^3=(x+y)^3 - 3xy(x+y)
=4^3 - 3(1)(4)
=12-12
=0
Hope this will help you
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