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If a,b,c are in AP, then prove that a^2 + c^2 - 2a(b-c) = 2a (b-c).
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Here s your answer
a^2 + c^2 -2a (b-c) = 2a (b-c)
a^2 + c^2 -2ab +2ac = 2a(b-c)
(a-c)^2 +2ab = 2a (b-c)
So
(a-c)^2 + 2ab = 2ab - 2ac
Hence verified!!
a^2 + c^2 -2a (b-c) = 2a (b-c)
a^2 + c^2 -2ab +2ac = 2a(b-c)
(a-c)^2 +2ab = 2a (b-c)
So
(a-c)^2 + 2ab = 2ab - 2ac
Hence verified!!
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