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4. For what value of a, the points (a, 1), (1, -1) and
(11, 4) are collinear ?
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slope of AB = Slop OF BC
-1 - 1 ÷ 1 -a = 4 + 1 ÷ 11 - 1
-2 ÷ 1 - a = 5 ÷ 10
1 - a = - 4
a = 5
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