Question

I will mark braniliest​

Answer 1

Answer:

hope it helps you

Step-by-step explanation:

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Answer 2

$(5 \times a) ^{b} = {5}^{3} \times {7}^{3} \\ \\ {5}^{b} \times {a}^{b} = {5}^{3} \times {7}^{3}$

comparing both sides

hence

${5}^{b} = {5}^{3} and \: {a}^{b} = {7}^{3}$

hence

b = 3. and. a= 7

2nd Q

$( { {2}^{a} })^{5} = {b}^{35} \\ \\ {2}^{a \times 5} = {b}^{7 \times 5}$

comparing both sides

hence 2=b

and a = 7

hope it helps ..

pls mark it as brainliest