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the sum of digits of a 2 digit number less than 20 is 5 find the number and the number formed by reversing its digits
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Step-by-step explanation:
Answer:let the two digits of a two digit number be X and Y.
Then the two digit number so formed is (10x+y),where X is at 10's place and Y is at unit place.
By question,
4 (X+y)=(10x+y)-18............(1)
And
4(X+y)=(10y+X)-9..............(2)
From above two equations we have,
10x+y-18=10y+x-9
Or,9x-9y-9=0
Or,x-y-1=0
Or,X=(1+y)
Using this value of X in (1) we get
4(1+y+y)=10(1+y)+y-18
Or,4+8y=10+11y-18
Or,12=3y
Therefore,y=4
Now X=(1+y)=1+4=5
Now required product of digits is
X*y=5*4= 20
hope it helps !!!!!
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