Question

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Answer 1

Colour after heating white

Equation  are as follow

At 63⁰C:

CuSO4.5H2O(s)→CuSO4.3H2O(s)+2H2O(g)

At 109⁰C:

CuSO4.3H2O(s)→CuSO4.H2O(s)+2H2O(g)

At 200⁰C:

CuSO4.H2O(s)→CuSO4(s)+H2O(g)

At 650⁰C:

CuSO4(s)→CuO(s)+SO3(g)

Answer 2

a) When blue copper sulphate Penta hydrate crystals are heated , it turns into colourless anhydrous copper sulphate.

On further heating it becomes $\bf{black}$ colour copper (II) oxide along with a liberation of sulphur trioxide.

b) Name of residue : $\boxed{Cuprous \: oxide}$

Formula of residue : $\boxed{CuO}$

Hope this helps!!