Question

I will mark it as brainliest plz solve it
For class IX

If 0.50 mole of monovalent metal (M+1) halide is mixed with 0.2 mole of a divalent metal (L+2) phosphate, the maximum number of moles of M3PO4 that can be formed is
(A)0.25 (B)0.30 (C)0.16 (D) 0.20

Answer 1

(c)1.66 moles of m3po3
6MX+L3(PO4)2>>>>2M3PO4+3LX2
MX here is the limiting reagent.