I will mark the correct answer as Brainliest
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hey dude , your answer is ---
let a , b and c are three sets of force
so, for equilibrium a , b and c form a closed triangle
now,
In a triangle of sides, a,b and c
a+b>ca+b>c so a>(c−b)a>(c−b)
b+c>ab+c>a so b>(a−c)b>(a−c)
c+a>bc+a>b so c>(b−a)c>(b−a)
Since three forces in equilibrium can be
represented as the three sides of a triangle and in a triangle each side (representing a force) is numerically greater than the different of the other two sides (forces), hence for equilibrium each force should be greater than or equal to the difference of the other two.
this is satisfied by only (3).
so , option 3 is right
hope it help you ★
let a , b and c are three sets of force
so, for equilibrium a , b and c form a closed triangle
now,
In a triangle of sides, a,b and c
a+b>ca+b>c so a>(c−b)a>(c−b)
b+c>ab+c>a so b>(a−c)b>(a−c)
c+a>bc+a>b so c>(b−a)c>(b−a)
Since three forces in equilibrium can be
represented as the three sides of a triangle and in a triangle each side (representing a force) is numerically greater than the different of the other two sides (forces), hence for equilibrium each force should be greater than or equal to the difference of the other two.
this is satisfied by only (3).
so , option 3 is right
hope it help you ★
Anonymous:
welcome
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