i will mark the fastest answer as brainliest...please answer it guyzz...fast...its urgent
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ABC is a right angles triangles
a/c to phythagoras theorem
H2=P2 +B2
AC2=AB2+BC2
25=AB2+2AD2
25=AB+2×3√5
2
25=AB2+9×5
25=AB2+45
AB2=20
AB=2√5
THEN
IN TRINGLES
EBC
EC2=EB2+BC2
CE2=5+9×5
CE2= 50
CE=5√2
a/c to phythagoras theorem
H2=P2 +B2
AC2=AB2+BC2
25=AB2+2AD2
25=AB+2×3√5
2
25=AB2+9×5
25=AB2+45
AB2=20
AB=2√5
THEN
IN TRINGLES
EBC
EC2=EB2+BC2
CE2=5+9×5
CE2= 50
CE=5√2
Ishanigupta:
the answer is 2 root 5
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Answer:
2√5
Step-by-step explanation:
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