I will mark the right answer as brainiest and please also write the steps.
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I think it will definitely help you
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Steps of constructions:
Draw a line AB= 4 cm
- FROM center B draw 4cm an arc and from center A draw another arc of 4cm.
- Now join AC and BC we get the equilateral triangle.
- From center A draw a ray back ward and point A1,A2,A3.
- Now join A3 to B
- from A2 join parallel to A3B
- Now from B' draw the 2/3 triangle
- You get your required triangle.
We get triangle A'BC' whose sides are of corresponding sides of triangle ABC and also a equilateral triangle.
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