Question

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Answer 1

(19-1) + (7) + (5) = 30

(15-1) + (9) + (7) = 30

(17-1) + (11) + (3) = 30








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Answer 2

Step-by-step explanation:

1,3,5,7,9,11,13,15

If we add any three of the given numbers then sum of three odd numbers can not be even and 30 is even

Then 30 can not be got we have to use other operations in addition of + operation

SOLUTION 1: Using factorial of 3 as 3!=6 is an even number

then possible solutions are

3!+7+17=30

3!+9+15=30

3! + 11+13=30

II Method: Using multiple operations

we make middle term =10 as followings

15+( 1+9 ) +5=30

13+( 1+9 ) +7 =30

15+( 3+7 ) +5=30

11+(3+7 ) +9 =30

15+( 11–1 ) +5 =30

13+( 11–1 ) +7 =30

15+( 13–3 ) +5=30

11+( 13–3 ) +9=30

13+( 15–5 ) +7=30

11+( 15–5 ) +9=30

Other solutions are possible by using other operations