Question

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Answer 1

Answer:

→Energy consumed by in day = Power × Time

→ 3×25×5 = 375Wh

→ Energy consumed in a 31 days

= 375×31 = 11625Wh

→ 11625 = 11.625KWh

→ 11.625 KWh = 11.625 units

Explanation:

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Answer 2

Question :

In a house 3 bulbs of 25 W each are used for 5 h a day. Calculate the units of electricity consumed in a month of 31 days

Solution :

Number of bulbs = 3

Power of each bulb = 25 W

Power of 3 bulbs = 3 × 25 (P) = 75 W

Time taken (t) = 5 h

Electrical Energy : It is defined as the energy equals to the product of power and time .

➳ E = P × t

➳ SI units : Joule

Energy Consumed by 3 Bulbs :

➠ E = P × t

➠ E = 75 × 5

➠ E = 375 J  $\pink{\bigstar}$

Energy Consumed for 31 Days :

➠ E' = 31 × E

➠ E' = 31 × 375

➠ E' = 11,625 J

➠ E' = 11,625 W-h

➠ E' = 11.625 Kw-h

➠ E' = 11.625 units  $\orange{\bigstar}$

Electrical energy consumed in a month of 31 days is 11.625 units .