Math, asked by bineetagarwal, 1 day ago

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Answered by rawat999
1
1)The ratio of their circumferences is 3:4.
2) (i) ratio of their circumferences is 3:5
(ii) ratio of areas is 9:25.
Answered by sarswatibisht13
0

Answer:

Step-by-step explanation:

answer 1:Let A1 = 9 and A2 = 16

Area of A1 / Area of A2 = 9 / 16

pi*r1^2 / pi*r2^2 = 9/16

r1 / r2 = 3 / 4

Now circumference is given by 2*pi*r

C1 : C2

= 2*pi*r1 : 2*pi*r2

= 2*pi*3 : 2*pi*4

= 3 : 4

Ratio of circumference is 3 : 4.

answer 2:ii) the radius of those circles be 3x and 5x respectively.

now area of 1st cirlce = π(3x)^2 = 9πx^2

area of 2nd circle = π(5x)^2 = 25πx^2

now their ratio becomes :

area of 1st cirlce: area of 2nd circle

9πx^2 : 25πx^2

= 9:25

i)Circumstance= 2πr ,so circumstance is directly proportional to radius so circumstance ratio is 3:5

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