i will mark u as brainliest pls answer this 18th and 23rd q
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0
when n(A)=n
n(B)=m
so,
n(A×B)=n(A)×n(B)
= m×n
= mn
hp!
n(B)=m
so,
n(A×B)=n(A)×n(B)
= m×n
= mn
hp!
Answered by
1
18th) (a1) = a as a 1×1 = 1 as in the exponent law. So a is common and power 1 is multiplied. To the 2nd power that is also 1 according to exponent law we multiply the 2 powers and it is 1 so we write it as a not as a1.
23) as n is common in the both factors and m is a new exponent so we take the common and the new exponent together and apply their powers to it. We see that the no of elements are 3 but n is common so there are 2. So A to the power mn × b to the power of n. There are 2 powers so they are m and n.
Plz mark me brainliest answer
23) as n is common in the both factors and m is a new exponent so we take the common and the new exponent together and apply their powers to it. We see that the no of elements are 3 but n is common so there are 2. So A to the power mn × b to the power of n. There are 2 powers so they are m and n.
Plz mark me brainliest answer
dhruvGHDY8:
thanks
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