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Answer:
1+ sinACosA
Step-by-step explanation:
L.H.S
[cos^2A/(1 - tanA) ]+ [sin^3A/(sinA - cosA)]
[cos^3A/- (sinA - cosA) ]+ [sin^3A/(sinA-cosA)]
= 1/(sinA-cosA) [ sin^3A - cos^3A]
= 1/(sinA - cosA)* [(sinA- cosA)(sin^2A + cos^2A + sinACosA )]
= sin^2A + cos^2A + sinAcosA
=1+sinAcosA R.H.S hence,proved
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