Math, asked by subhikshamrth15, 10 months ago

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Answers

Answered by TheLostMonk
1

Answer:

1+ sinACosA

Step-by-step explanation:

L.H.S

[cos^2A/(1 - tanA) ]+ [sin^3A/(sinA - cosA)]

[cos^3A/- (sinA - cosA) ]+ [sin^3A/(sinA-cosA)]

= 1/(sinA-cosA) [ sin^3A - cos^3A]

= 1/(sinA - cosA)* [(sinA- cosA)(sin^2A + cos^2A + sinACosA )]

= sin^2A + cos^2A + sinAcosA

=1+sinAcosA R.H.S hence,proved

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