Math, asked by TITANGAMING72, 1 month ago

i will mark u as brainlist pls tell this​

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Answered by archisha3012
0

Answer:

hope my answer helps you

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Answered by ahamdshahbaj
0

Answer:

a =  \frac{1}{ \sqrt{3}  - \sqrt{2}  }  \times  \frac{ \sqrt{3}   +  \sqrt{2} }{ \sqrt{3}  +  \sqrt{2} }  \\   = \sqrt{3}  +  \sqrt{2}  \\

b =  \frac{1}{ \sqrt{3} +  \sqrt{2}  }  \times  \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3} -  \sqrt{2}  }  \\  =  \sqrt{3 }  -  \sqrt{2}  \\

 {a}^{2}  +  {b}^{2}  - 5ab \\  {( \sqrt{3} -  \sqrt{2} ) }^{2}  + ( { \sqrt{3} -  \sqrt{2})  }^{2}  - 5( \sqrt{3}  -  \sqrt{2} ) \times ( \sqrt{3}   +  \sqrt{2} ) \\  = 3 + 2 - 2 \times  \sqrt{2 \times3}  + 3 + 2 + 2 \times  \sqrt{2 \times 3}  - 5 \times (3 - 2) \\ 5 + 5 - 5 \times 1 \\  = 10 - 5 \\  = 5

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