Question

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Answer 1

Answer:

quadratic equation=ax^2 + bx + c

Zeroes of eq.= 3 , -3

Therefore (x-3) & (x+3)are factors of equation.

let x = 3 be alpha

x = -3 be beta

alpha + beta = -b/a

3 - 3 = -b/a

0 = -b & a = 1

alpha × beta = c/a

3×-3 = c/a

-9 = c

a = 1

therefore the required quadratic equation is x^2 + 0x - 9

Answer 2

Answer:

Roots of Quadratic equation ☹

3 and -3

So x = 3 or x = -3

(x - 3) (x + 3) = 0

x(x + 3) -3(x+ 3)= 0

x² + 3x -3x - 9 = 0

x² + 0x - 9 = 0 is your required equation