I will mark u as the brainlist
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x²-2bx+(b²-a²)=0
x^2-2bx(b+a)(b-a)=0
x(x-2b)(b*b+b*a-a*a+b*a=0
x(x-2b)(b^2+ab-a^2+ba=0
Sorry I can do it till here only
Sorry
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Answer:
x = a+b, b-a
Step-by-step explanation:
x²-2bx+b²-a²=0
x²-2*(x)(b)+b²-a² =0
(x-b)²-a²=0
(x-b+a)(x-b-a)=0
x-b+a=0
x=b-a
or x-b-a=0
x=a+b
hence
x=a+b,b-a
Anonymous:
ok dear thanx
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