Math, asked by yatharthjain12p96ey7, 1 year ago

I will mark u as the brainlist​

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Answers

Answered by Shreyabh121
0

x²-2bx+(b²-a²)=0

x^2-2bx(b+a)(b-a)=0

x(x-2b)(b*b+b*a-a*a+b*a=0

x(x-2b)(b^2+ab-a^2+ba=0

Sorry I can do it till here only

Sorry

Answered by Anonymous
0

Answer:

x = a+b, b-a

Step-by-step explanation:

x²-2bx+b²-a²=0

x²-2*(x)(b)+b²-a² =0

(x-b)²-a²=0

(x-b+a)(x-b-a)=0

x-b+a=0

x=b-a

or x-b-a=0

x=a+b

hence

x=a+b,b-a


Anonymous: ok dear thanx
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