Math, asked by riy0911, 8 months ago

I will mark u brainlist
if u will answer this questiin correctly...

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Answers

Answered by saikethan24
1

Step-by-step explanation:

Given:

sin^3A+cos^3A/sinA+cosA +sinAcosA

= we know that sin^3A+cos^3A= (sinA+cosA)(sin^2A+cos^2A-sinAcosA)

and also......sin^2A+cos^2A=1

by putting the values.....

(sinA+cosA)(sin^2A+cos^2A-sinAcosA)/sinA+cosA + sinAcosA

by cancelling (sinA+cosA)...

sin^2A+cos^2A-sinAcosA+sinAcosA

by cancelling sinAcosA....

=sin^2A+cos^2A=1

Hence proved....

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