Question

I will mark you as a brainlist if you answered step by step. in tri ABC , AD is angle bisector of angle BAC . if B-D-C, AB=8 ,BD=6, and DC=3, rhen find side AC=?​

Answer 1

Answer:

your answer

Step-by-step explanation:

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Answer 2

Answer:

Here's your Answer.

Step-by-step explanation:

The Line AD is dividing the traingle in 2 halves. Over here we can use Pythagoras theorem.

Hypotenuse ^2 = Side 1 ^2 + side 2^2

Hypotenuse ^2 = 8^2 + 6^2

Hypotenuse ^2 = 64+36

Hypotenuse ^2 = 100

Hypotenuse = 10

Now the other half triangle again the same formula.

10^2 = 3^2 + AC^2

100 = 9 + AC^2

AC^2 = 100-9

AC^2 = 91

AC = $\sqrt9$1

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