Math, asked by VasuBhagy, 8 months ago

I will mark you as brainliest ​

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Answered by shellyvg100
3

1 is the correct answer

DO MARK AS BRAINALIST

Answered by abhinayasiddaraju
1

HI !

tanθ = 20/21 = opposite side(o)/adjacent side(a)

hypotenuse = h = o² + a²

Let , o = 20k  and a = 21k

h² = (20k)² + (21k)²

   = 841k²

h = 29 k

sinθ = o/h 

        = 20k/29k

        =20/29

cosθ = a/h

         = 21k/29k

        = 21/29

1 - sinθ + cosθ ÷ 1 + sinθ + cosθ

= {1 - 20/29 + 21/29 / 1 } ÷ {1 + 20/29 + 21/29}

= {29/29 - 20/29 + 21/29) ÷ {29/29+20/29+21/29}

= {29 - 20 + 21/29} ÷ {29+20+21/29}

= 30/29 ÷  70/29

29 gets cancelled on both denominator and numerator.

= 30/70

= 3/7

= RHS

Proved.

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