Question

I will mark you as brainliest

factorise-
12(a+1)²-25(a+1)(b+2)+12(b+2)²


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Answer 1

$12(a + 1) {}^{2} - 16( a+ 1)( b+ 2) - 9( a+ 1)( b+ 2) + 12 { b+ 2}^{2} \\ = > 4( a+ 1)(3( a+ 1) - 4(b + 2)) - 3(b + 2)(3( a+ 1) - 4( b+ 2)) \\ = > (4( a+ 1) - 3( b+ 2))(3( a+ 1) - 4( b+ 2)) \\ = > factors \: are \boxed{ (4( a+ 1) - 3( b+ 2))}\boxed{(3( a+ 1) - 4( b+ 2))} \:$

hope it helps you

Answer 2

Answer:

hey mate here your answer..

Step-by-step explanation:

=12(a.sq+1.sq+1a)-25(a+1)(b+2)+11(b.sq+2.sq+2b)

=(12a.sq+12.sq+12a)-(25ab+ 50a+25a+50)+(11b.sq+22sq+22b)

=144+144+12a-25ab-50a-25a-50+121b+484+22b

=now you can solve it ....by add a all and b all and number

thanks You