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factorise-
(a-b)³+(b-c)³+(c-a)³
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Let x = (a – b), y = (b – c) and z = (c – a) Consider, x + y + z = (a – b) + (b – c) + (c – a) = 0 ⇒ x3 + y3 + z3 = 3xyz That is (a – b)3 + (b – c)3 + (c – a)3 = 3(a – b)(b – c)(c – a)
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