Math, asked by mohammadzeeshan0988, 23 days ago

i will mark you as brainlist ​

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Answered by jesnazakkariyya
0

Answer:

Mark me first plz

So let me give the answer

.

I forgot plz forgive me

Answered by Anonymous
2

{\bold{\green{\underline{\underline{Given \:  Equation :- }}}}}

 \sf \: k x {}^{2}  + 6x + 11 \\

We know the General equation of quadratic equation : \boxed{ax {}^{2}  + bx + c = 0}

For Real Roots : \boxed{ \sf \: b {}^{2}  - 4ac \geqslant 0}

$\underline{\fbox{${◇ Required \:  Solution}$}}$

  = (6) {}^{2}  - 4 \times k \times 11  \geqslant 0\\ =  36 - 44k \geqslant 0 \\  \implies36 \geqslant 44k \\   \implies9 \geqslant 11k \\  \\  \implies \frac{9}{11}  \geqslant k \\  :  \implies \:  \boxed{ \green{\sf \: k \leqslant  \frac{9}{11}} }

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