Question

i will mark you as brainlist ans pls
​

Answer 1

Answer:

Step-by-step explanation:

Given points A(1,5) B(4,2) C(-2,2)

Length and of AB= √[(x2-x1)^2+(y2-y1)^2]

= √[(4-1)^2+(2-5)^2]

= √(3)^2+(-3)^2

= √9+9= √2(9) =3√2

Similarly,

Length of BC =6

Length of AC =3√2

Perimeter of Triangle ABC

=length of (AB+BC+AC)

=3√2+6+3√2

=6+6√2=6(√2+1)

In calculating length of the side I have done only one completely and for others I have given direct answers

So, pls try remaining urself

I hope u have understood my concern