Question

I will mark you as brainlist if you answered with explanation. Q : ABC ~ PQR and <Q = <B= 90 ,<R = 30 then find <A= ?​

Answer 1

$ans. \: \: in \:∆ abc \\ ∆a + ∆b + ∆c = 180⁰ \: (by \: angle \: of \: sum \: property)</p><p> \\ ∆a + 90⁰ + 30⁰ = 180⁰ \\ ∆a + 120⁰ = 180⁰ \\ ∆a = 180⁰ - 120 ⁰ \\ ∆a = 60⁰ \\ \\ in \: ∆pqr \\ ∆p + ∆q + ∆r = 180⁰ (by \: angle \: of \: sum \: property) \\ ∆p + 90⁰ + 30⁰ = 180⁰ \\ ∆p + 120⁰ = 180⁰ \\ ∆p = 180⁰ - 120 ⁰ \\ ∆p = 60⁰ \\ \\∆ a =∆ p \\∆ b = ∆q \\ ∆c =∆ r \\ \\ ∆ abc \: is \: similar \: to \: ∆pqr. \: (by \: aaa \: criteria) \: \: \: \: ans.$