I WILL MARK YOU AS BRILLIANT IF YOU ANSWER MY QUESTION6.If x+y=5 ,xy=6 and x 2+y 2=13 find x 3 - y 3
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Answered by
3
Hi friend!!
Given, x+y=5--------(1)
Squaring on both sides, we get
x²+y²+2xy=25
Given, xy=6-----(2)
→x²+y²+2(6)=25
x²+y²+12=25
x²+y²=13--------(3)
Now, x³+y³=(x+y)(x²+y²-xy)
From (1),(2),(3) we get
x³+y³=5(13-6)
=5(7)=35
I hope this will help you ;)
plz mark me as a brainliest answer
Answered by
0
Answer:
x + y = 5 xy = 6 x^2+y^2 = 13
(x - y)^2 = (x+y)^2 - 4xy
x - y = ✓(x+y)^2 - 4xy
x - y = ✓25+24 = ✓49 = 7
x^3 - y^3
= (x - y) [(x)^2 + x.y + (y)^2]
= (7) [13+6]
= 7 × 19
= 133
hope it helps you
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