Question

I WILL MARK YOU AS BRILLIANT IF YOU ANSWER THIS Evaluate 99 x 102 using suitable identity

Answer 1

Answer:

It is known that,

(a+b)3=a3+b3+3ab(a+b)and(a−b)3=a3−b3−3ab(a−b)

(i) (99)3 = (100 − 1)3

= (100)3 − (1)3 − 3(100) (1) (100 − 1)

= 1000000 − 1 − 300(99)

= 1000000 − 1 − 29700

= 970299

(ii) (102)3 = (100 + 2)3

= (100)3 + (2)3 + 3(100) (2) (100 + 2)

= 1000000 + 8 + 600 (102)

= 1000000 + 8 + 61200

= 1061208

(iii) (998)3= (1000 − 2)3

= (1000)3 − (2)3 − 3(1000) (2) (1000 − 2)

= 1000000000 − 8 − 6000(998)

= 1000000000 − 8 − 5988000

= 1000000000 − 5988008

= 994011992

Step-by-step explanation:

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Answer 2

Here is your answer dude.

99 × 102

=(100-1) (100+2)

=10000+200-100-2

=10098 ----------Ans.