Question

I will mark you as the brainiest if you get it correct Can someone help me on this question please This homework is due tomorrow and it needs to be done on time I will mark you as the brainiest if you get it correct Thank you And if you don't put an answer i will report you No hard feelings thx Can you work out The Area of BOTH of the triangles please thank you much appreciated

Answer 1

Question :-

Calculate the area of the trapezium ?

$\setlength{\unitlength}{4}\begin{picture}(0,0)\put(30,-2){ \tt{5\:cm} } \put(12, - 12){ \tt{8 \: cm} }\put(13,10){ \tt{6 \: cm} }\put(2,-2){ \tt{4\: cm} }\put(-5,6){ \tt{D} }\put(28,6){ \tt{C} }\put(-12,-8){ \tt{A} }\put(31,-8){ \tt{B} }\put(1,8){\line(0,-6){17}}\put(30.3,-8.8){\line(-4,0){39.5}}\put(26,8){\line(1,-4){4.2}}\put(1,8){\line(8,0){25}}\put(1,8){\line(-2,-13){10}}\put(35, - 15){ \tt{@MisterIncredible} }\end{picture}$

Answer :-

Required to find :-

• Area of the Trapezium ?

Formula used :-

$\boxed{\rm{Area \ of \ the \ trapezium = \dfrac{1}{2}h(a + b)}}$

Solution :-

From the figure we can conclude that ,

Parallel sides of the Trapezium = 8 cm & 6 cm

Similarly,

Distance between the parallel sides = 4 cm

So,

Using the formula ,

$\boxed{\rm{Area \ of \ the \ trapezium = \dfrac{1}{2}h(a + b)}}$

here,

• h = perpendicular distance between the parallel sides ( height )

• a , b are the lengths of the two parallel sides

Hence,

$\longrightarrow{\tt{Area \ of \ the \ trapezium = \dfrac{1}{2} \times 4 ( 8 + 6 ) }}$

$\longrightarrow{\tt{Area \ of \ the \ trapezium = \dfrac{1}{2} \times 4 ( 14 )}}$

$\longrightarrow{\tt{ Area \ of \ the \ Trapezium = \dfrac{1}{ \cancel{2} } \times \cancel{4} ^2 ( 14 ) }}$

$\longrightarrow{\tt{ Area \ of \ the \ Trapezium = 2 \times 14 }}$

$\longrightarrow{\tt{ Area \ of \ the \ Trapezium = 28 }}$

Therefore,

Area of the Trapezium = 28 cm²

Additional Information :-

1. A quadrilateral in which one pair of opposite sides are equal then it is called as " Trapezium " .

2. Perimeter of the Trapezium = Sum of all its sides

3. The distance between the parallel sides is known as the perpendicular height of the Trapezium .

4. If the non-parallel sides are equal then it is a isosceles Trapezium .

Answer 2

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Question}}}}}}}$

$\setlength{\unitlength}{4}\begin{picture}(0,0)\put(30,-2){ \tt{5\:cm} } \put(12, - 12){ \tt{8 \: cm} }\put(13,10){ \tt{6 \: cm} }\put(2,-2){ \tt{4\: cm} }\put(-5,6){ \tt{S} }\put(28,6){ \tt{R} }\put(-12,-8){ \tt{P} }\put(31,-8){ \tt{Q} }\put(1,8){\line(0,-6){17}}\put(30.3,-8.8){\line(-4,0){39.5}}\put(26,8){\line(1,-4){4.2}}\put(1,8){\line(8,0){25}}\put(1,8){\line(-2,-13){10}}\put(35, - 15){ \tt{\:\:\:} }\end{picture}$

Find the area of the trapezium

$\sf{\huge{\bold{\pink{\bigstar{\boxed{\boxed{Solution}}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Height = 4cm
• length of parallel sides = 6cm and 8cm

$\sf{\bold{\blue{\underline{\underline{To\:find}}}}}$

• Area of the trapezium = ????

$\sf{\bold{\purple{\underline{\underline{Explanation}}}}}$

$\sf{\bold{\red{\boxed{area \:of\: trapezium = \dfrac{1}{2}\times height\times sum \: of \: parallel \: sides }}}}$

$\sf{area = \dfrac{1}{\cancel 2}\times \cancel 4 \times (6 + 8)}$

$\sf{area = 2\times 14}$

$\sf{area = 28cm^2}$

$\sf{\bold{\orange{\boxed{area = 28cm^2 }}}}$

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