Math, asked by Sundersaritha, 9 months ago

I WILL MARK YOU AS THE BRILLLIANT Find the expansion of(2x+3y+4z) 2 . ii)(x-2y+3z) 2

Answers

Answered by ambarkumar1
0

Step-by-step explanation:

i)

(2x + 3y + 4z) {}^{2}  = (2x) {}^{2}  + (3y) {}^{2}  + (4z) {}^{2}  + 2(2x)(3y) + 2(3y)(4z) + 2(4z)(2x) \\   = 4x {}^{2}  + 9y {}^{2}  + 16z {}^{2}  + 12xy + 24yz + 16zx \\

ii)

(x - 2y + 3z) {}^{2}  = x {}^{2}  +( - 2y) {}^{2}  + (3z) {}^{2}  + 2(x)( - 2y) + 2( - 2y)(3z) + 2(3z)(x) \\  = x {}^{2}  + 4y {}^{2}  + 9z {}^{2}   - 4xy - 12yz + 6z

Answered by tanejakomal046
1

Step-by-step explanation:

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