Question

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Answer 1

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Answer 2

Length of the arcAB = 13.2 cm

We know,

$\text{Length of arc = 2πr} \frac{ \theta}{360 \degree} \\ \\ \to13.2 = 2 \times \frac{22}{7} \times 14 \times \frac{\theta}{360\degree} \\ \\ \to \frac{\theta}{360\degree} = \frac{13.2}{2 \times \pi \times 14 }$

Now,

Area of the sector

$\huge \to \boxed{\pi {r}^{2} \frac{\theta}{360} } \\ \\ \\ \to\pi \times {14}^{} \times 14 \bigg(\frac{13.2}{2 \times \pi \times 14} \bigg) \\ \\ \to \cancel\pi \times {\cancel{14}}^{} \times 14 \bigg(\frac{13.2}{2 \times \cancel\pi \times \cancel{14}} \bigg) \\ \\ \to \frac{14 \times 13.2}{2} \\ \\ \to14 \times 6.6 \\ \\ \to \sf \red{92.4 \: \: {cm}^{2} }$