Question

I WILL MARK YOU BRAINLIEST a piston of cross sectional area 100cm square is used in a hydraulic press to exert a force of 10 power 7 dynes on the water. the cross sectional area of the other piston which supports a truck of mass 2000 kg is
a) 9.8 into 10 square

b)9. 8 into 10 cube

c) 1.96 into 10 cube

d) 1.96 into 10 power 4

Answer 1

Answer:

Option d) 1.96 × 10⁴ cm²

Given:

Force on first piston, F1 = 10⁷ dynes = 10² N

Cross section area of first piston, A1 = 100 cm² = 0.01 m²

Force of other piston, F2 = 2000 kg wt = 2000 × 9.8 = 19,600 N

To find:

Cross section area of other piston = A2

Solution:

By Pascal's law, we know

P1 = P2

where, P is pressure.

Here,

$\dfrac{F_{1}}{A_{1}} = \dfrac{F_{2}}{A_{2}}$

$\implies \dfrac{100}{0.01} = \dfrac{19600}{A2} \\ \\ \implies \: A2 = \frac{19600 \times 0.01}{100} = 1.96 \: {m}^{2} \\ \\ \implies A2= 1.96 \times {10}^{4} {cm}^{2}$

Therefore, cross section area of other piston is 1.96 × 10⁴ cm²

Answer 2

Given:

F1 = 10⁷ dynes = 10² N

A1 = 100 cm² = 0.01 m²

F2 = 2000 kg wt = 2000 × 9.8 = 19,600 N

To find:

Cross section area of other piston (A2)

Solution:-

By Pascal's law,

P1 = P2

where, P is pressure.

Here,

=> F1/A1 = F2/A2

=> 100/0.01 = 19600/A2

=> A2 = 19600*0.01 / 100

=> A2 = 1.96cm^2.

Hence , cross section area of other piston is 1.96 × 10⁴ cm²

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