I will mark you brainlist please help. For what value of k the following equation will be a quadratic equation ( 2k-1 )x2 + kx + 3 = 0.
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in this you have to put the value of k so the value of k is 1so your equation is looks like. X2+1x+3=0the solve it hope it's correct
Mmgg:
Plz do step by step
yes pz
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p(x) = (2k - 1)x^2 + kx + 3 = 0
= (2k - 1)x^2 + kx + 3 = 0
D ^2 = 4 ac
= 4 * 2k -1 * 3
= 4* 6k - 3
= 24k - 12
lets take D = 0
24k = 12
k = 12 / 24
k = 1 / 2
= (2k - 1)x^2 + kx + 3 = 0
D ^2 = 4 ac
= 4 * 2k -1 * 3
= 4* 6k - 3
= 24k - 12
lets take D = 0
24k = 12
k = 12 / 24
k = 1 / 2
from where d and ac
d utakeit as the determinant and a and c are the coefficient
between 2k-1 and 2 that is not multiply sign but that is x alphabet.plz solve again
Plz help
dude the ans is same
i modified it
The ans is except 1/2 not equal to 1/2.
whats the value of x
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