Question

I will mark you the BRAINLIEST!!!

Compound 'A' has molecular formula $C_{20}H_{30}O$ and Compound 'B' has molecular formula $C_{20}H_{28}O$. How many moles of Compound 'B' will have same number of atoms as are present in 1 mol of Compound 'A'?

Answer 1

Given:

The molecular formula of A = C₂₀H₃₀O

The molecular formula of B = C₂₀H₂₈O

To Find:

The no of moles of Compound 'B' that will have the same no of atoms as are present in 1 mole of Compound 'A'.

Calculation:

- The no of atoms in 1 molecule of A = 51

- The total no of atoms in 1 mole of A = 51 × 6.022 × 10²³

- The no of atoms in 1 molecule of B = 49

- The total no of atoms in 1 mole of B = 49 × 6.022 × 10²³

- The no of moles of B in 51 × 6.022 × 10²³ atoms =  (51 × 6.022 × 10²³)/ (49 × 6.022 × 10²³)

⇒ The total no of moles of B = 51/49

- Hence, the correct answer is option (a) 51/49.