Question

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Question =》The value of cos 0°+ cos pi/7+cos2pi/7+cos 3pi/7+..........+cos6pi/7 is equals to

Answer 1

Answer:

1

Step-by-step explanation:

cos(π-θ) = -cos(θ)

using the above logic,

cos(6π/7) = cos(π - π/7) = -cos(π/7)

cos(5π/7) = cos(π - 2π/7) = -cos(2π/7)

cos(4π/7) = cos(π - 3π/7) = -cos(3π/7)

adding all of them, you'll be left with cos(0°) = 1

Ans: 1

Answer 2

Step-by-step explanation:

Refer to the attachment...