i will marked the fastest answer as brainliest..please answer both these questions..
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second answer
n (S) =52
let the event be A
n (A) = 21.....since there are 23 red cards and 2 queens excluding red cards'
P (A)= n (A)/n (S)
= 21/52
hope this helps...
n (S) =52
let the event be A
n (A) = 21.....since there are 23 red cards and 2 queens excluding red cards'
P (A)= n (A)/n (S)
= 21/52
hope this helps...
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Ishanigupta:
are u sure that the first answer is 1:1
sorry dear .....I thought ratio of their areas are asked...I 'll rectify that immediately
pretty sure about the second one
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Answer of your question 20 is 2/√π
And of 21 is 6/13
number of cards which are red or queen =26+2=28
p(getting either red card or queen)=number of cards which are red or queen ÷ total number of cards
= 28/52 =7/13
Now,
p(not getting either red card or queen)=1- p( either getting red card or queen)
1-7/13
=13-7/13
=6/13
And of 21 is 6/13
number of cards which are red or queen =26+2=28
p(getting either red card or queen)=number of cards which are red or queen ÷ total number of cards
= 28/52 =7/13
Now,
p(not getting either red card or queen)=1- p( either getting red card or queen)
1-7/13
=13-7/13
=6/13
actually i need the amswer with explanation
pls explain 6/13
i just explained
i can explain it in other way also
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