Question

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A car moving with speed of 50 km/hr,can be stopped by brakes after at least 10m at what rate the velocity is decreasing in the motion

Answer 1

Answer:

32 is the answer

Explanation:

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Answer 2

Answer:

9.64 m/s²

Explanation:

Here,

Initial velocity = 50 km/hr = (50*5/18) m/s

Initial velocity = 125/9 m/s

Displacement = 10 m.

As the car stops, final velocity is 0.

• v = 0
• u = 125/9
• S = 10

Using equations of motion-

• v^2 = u^2 + 2aS

= > 0^2 = (125/9)^2 + 2a(10)

= > 0 = 15625/81 + 20a

= > - 15625/81 = 20a

= > - 9.64 ≈ a

Magnitude of a = | - 9.64 | = 9.64

Hence the rate of velocity is 9.64 m/s²