Math, asked by shinchan06, 1 year ago

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Answered by mokshil1

x-1=0
x=1
ax³-bx²+x-6=4
4=a(1)³-b(1)²+1-6
4=a-b-5
a-b=9_____eq.1
AS x-2 is the factor of the polynomial ax³-bx²+x-6
x-2=0
x=2
a(2)³-b(2)²+2-6=0
8a-4b-4=0
4(2a-b-1)=0
2a-b=1_____eq.2
solving both the equations.
2a-b=1
a-b=9
- + -
_________
a =-8
substituting value of -8 in equation 1(as it's the easier one)
-8-b=9
b=-17
therefore the value of a is -8 and value of b is -17

hope it helped ☺

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Answered by ROWNAKSAI

Answer:

x-1=0

x=1

ax³-bx²+x-6=4

4=a(1)³-b(1)²+1-6

4=a-b-5

a-b=9_____eq.1

AS x-2 is the factor of the polynomial ax³-bx²+x-6

x-2=0

x=2

a(2)³-b(2)²+2-6=0

8a-4b-4=0

4(2a-b-1)=0

2a-b=1_____eq.2

solving both the equations.

2a-b=1

a-b=9

- + -

_________

a =-8

substituting value of -8 in equation 1(as it's the easier one)

-8-b=9

b=-17

therefore the value of a is -8 and value of b is -17

Step-by-step explanation:

Hope it is helpful for you☺️☺️

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